An
ideal gas undergoes an isothermal expansion at
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Solution: Click For PDF Version Let us recall that in an isothermal process there is no change in the internal energy. Therefore, the work done by the gas in isothermal expansion from initial volume
to final volume
will be equal in magnitude to the amount of heat absorbed. The work
done by the gas (n
moles) in isothermal expansion from volume
to volume
will be
Therefore, the heat absorbed, Q, in isothermal expansion of n moles of an ideal gas will be
The change in entropy of n moles of an in isothermal expansion will therefore be
Data of the problem are
and
We have
or
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,
increasing its volume from 1.3 to
3.4 L. The entropy change of the gas is
.
We have to find the amount of gas present in moles.
