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247.


Problem 26.6 (RHK)


A gasoline internal combustion engine can be approximated by the cycle shown in the figure. We will assume that an ideal diatomic gas is used in the cycle and a compression ratio of 4:1 (). We will further assume that . (a) We have to determine the pressure and temperature of each of the vertex points of the pV diagram in terms of and . (b) We have to calculate the efficiency of the cycle.

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(a)

It is given that the gasoline internal combustion engine can be approximated by an ideal diatomic gas. Therefore, the ratio of specific heats for this gas will be

(diatomic ideal gas)

Let the volume, pressure, and temperature of the gas at the point a in the pV diagram be , , and , respectively.

It is given that at the point b in the cycle, . From the pV diagram, we note that .

From the ideal gas equation we note that temperature at b will be

Part bc of the cycle is an adiabatic process. In an adiabatic process

Therefore, we have

Or

as

Temperature at c will be

.

Also, the part dc of the cycle is an adiabatic process. Therefore,

And temperature at d will be


(b)

Process ab (spark) takes place at constant volume, therefore no work is done on the gas and the heat absorbed will be equal to the increase in the internal energy. That is

We have assumed that the amount of gas undergoing the cyclic process is n moles and that it is an ideal diatomic gas.

Process bc is adiabatic. Therefore, there is no exchange of heat with the external system. In an adiabatic process the work done is given by

Therefore,

And the work done on the gas during the adiabatic process da will be

For the sake of completeness, we calculate the amount of heat released by the gas to the external system during the process cd (intake). We have

The total amount of work done on the gas during one cycle will be

As this work is negative, we can say that the work done is done by the engine during one cycle on the external system.

Therefore, the efficiency of the engine is

That is the efficiency of the engine is 42%.