A mercury-filled manometer with two unequal-length arms of the same cross-sectional area is sealed off with the same pressure in the two arms. With the temperature constant, an additional of mercury is admitted through the stopcock at the bottom. The level on the left increases 6.0 cm and that on the right increases 4.0 cm. We have to find the pressure .
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Solution: Click For PDF Version Let the cross-sectional area of the arms of the manometer be . The initial volume of the gas in the left-arm of the manometer will be
and the initial volume of the right-arm of the manometer will be . It is given that the pressure of gas in both arms of the manometer is . When at constant initial temperature an additional of mercury is introduced in the manometer it is given that the level of mercury in the left-arm rises by 6.0 cm and that in the right-arm by 4.0 cm. The changed volume of the gas in the left-arm after mercury has been added will be
and the changed volume of the gas in the right-arm will be
Let the changed pressure in the left-arm be and that in the right-arm be . As the temperature has remained constant in the process, we have
Similarly, we have
We now require that at the same level of mercury in both the arms of the manometer the pressure has to be equal. This gives the condition
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