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206.


Problem 23.13 (RHK)


Container A contains an ideal gas at a pressure of and a temperature of 300 K. It is connected by a thin tube to container B with four times the volume of A. B contains the same ideal gas at a pressure of and at a temperature of 400 K. The connecting valve is opened, and equilibrium is achieved at a common pressure while the temperature of each container is kept constant at its initial value. We have to find the final pressure in the system.


Solution:           Click For PDF Version

Let the initial amounts of ideal gas in the container A be and that in the container B be , respectively. Let the volume of the container A be V. Temperature of the gas in A is 300 K and the pressure of the gas in A when it is isolated from B is given to be. The volume of the container B is 4 V and its temperature is 400 K and the pressure of the gas in it when it is isolated from A is given to be . From the ideal gas equation, we have

The total amount of gas in containers A and B is therefore

.

The connecting valve is opened and equilibrium is achieved by marinating the temperatures of A and B. Let the common pressure in the containers be P when equilibrium has been reached. Let the amount of gas in the container A at equilibrium be . The amount of gas in the container B at equilibrium will be . We have the following equations describing this situation:

Therefore,