927. Problem 56.33 (RHK) We have to show (a) that the number N of photons radiated, per unit area per unit time, by a cavity radiator at temperature T is given by In evaluating the integral, we will ignore “1” in the denominator of . (b) We have to show that to the same approximation, the fraction of photons by number, with energies greater than 2.2 MeV at a temperature of is . |
Solution: Click For PDF Version The radiated power per unit area that extends from to is given by the Planck’s blackbody radiation law, . The energy of a photon of wavelength is . Therefore, the number of photons having wavelength emitted per unit area per second by a blackbody at temperature T will be given by , and therefore, the number N of photons radiated, per unit area per unit time, by a cavity radiator at temperature T will be given by In evaluating the integral, we will ignore “1” in the denominator of . In this approximation For evaluating this integral, we make the change of variable Stefan-Boltzmann constant We thus find that (b) We will show that to the same approximation, the fraction of photons by number, with energies greater than 2.2 MeV at a temperature of is . Photons with energy greater than 2.2 MeV will have wavelength , Therefore, And, Therefore, And,
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