Ordinary water consists of 0.015% by mass of “heavy water,” in which one of the two hydrogen atoms is replaced with deuterium, . We have to estimate the average fusion power that could be obtained if we “burned” all the in 1 litre of water in 1 day through the reaction .

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Ordinary water consists of 0.015% by mass of “heavy water,” in which one of the two hydrogen atoms is replaced with deuterium, . Therefore, mass of “heavy water” in 1 litre of water will be

.

Number of molecules of “heavy water” in 0.15 g, which will also be the number of , will be

In fusion of two nuclei through the process

,

3.27 MeV energy is released. Therefore, the total energy that can be released by burning off all nuclei contained in 1 litre of water will be

If the burning of nuclei contained in 1 litre of water occurs in 1 day , the average fusion power that will be available will be