Solution:
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We consider a fission of
by fast
neutrons in which no neutrons were emitted. The final stable end products, after
the beta-decay of the primary fission fragments, are
and
.
(a)
We note that as the atomic number of uranium, ,
is 92, the conservation of charge tells us that the total combined number of
protons in the primary fission fragments of the
nuclide will also be 92.
The atomic number of cerium, ,
is 58 and that of ruthenium, ,
is 44 the combined number of protons in the
and
nuclides
will be 102. Therefore, a total of 10 beta-decays would have taken place for 10
neutrons to have changed into 10 protons by emission of 10 electrons by beta
emissions.
(b)
We will calculate the
value
for the fission by considering the effective nuclear process

As we use the atomic masses instead of the masses of the nuclides, the
will be given by

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