Solution:
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,
atomic mass = 239 u, decays by
decay
with a half-life of 24,100 y. The decay constant of
will
therefore be

The atomic mass of
is 239 u. Therefore, the number of nuclides in a 12.0 g sample of pure
will be

In 20,000 y the number of
particles produced by radioactive decay of
nuclides would be given by

As
particle is a helium nucleus and has an atomic mass of 4.00 u the amount of
helium produced by 12.0 g of
in
20,000 y will therefore be

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