805. Problem 53.29 (RHK) For silver, we have to calculate (a) the mean
free path of conduction electrons and (b) the ratio of mean free path to the
distance between neighbouring ions. Silver has a Fermi energy of 5.51
eV and a resistivity of
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Solution: Click For PDF Version Resistivity of a metal is given in terms of the density of
conduction electrons,
In problem 804
Therefore, the mean time for collision of a conduction electron with a silver ion at the lattice will be As conduction electrons will have speed of about
We calculate next the distance between neighbouring ion
cores. Let us assume that each ion core is contained inside a cubical lattice of
length
We find We estimate the ratio of the mean free path to the distance between neighbouring ion cores. It is given by
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