741. Problem 39.79P (HRW) A proton and a deuteron (the latter has the same charge as a proton but twice the mass) strike a potential energy barrier that is 10 fm thick and 10 MeV high. Each particle has a kinetic energy of 3.0 MeV before it strikes the barrier. We have to find (a) the transmission probability for each; (b) their respective kinetic energies after they pass through the barrier (assuming that they do so); and (c) their respective kinetic energies if they are reflected from the barrier. |
Solution: Click For PDF Version We will need the following data: Mass of a proton,
Mass of a deuteron,
The transmission probability of a particle of mass m, energy E through a barrier of height U and width L is given approximately by the function
Thickness of the barrier,
height of the barrier,
kinetic energy of the protons and kinetic energy of the deuterons before they
strike the barrier are equal and each is
(a) We calculate next the transmission probabilities. Transmission probability for a proton to tunnel through the barrier will be And, the transmission probability for a deuteron to tunnel through the barrier will be (b) After tunnelling through the barrier, protons and neutrons move through a zero potential region, the kinetic energy of each will therefore be 3.0 MeV. (c) On reflection from the barrier, protons and neutrons move through a zero potential region, the kinetic energy of each will therefore be 3.0 MeV.
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