736. Problem 50.29 (RHK) We have to calculate (a) the smallest allowed
energy of an electron confined to an infinitely deep well with a width equal to
the diameter of an atomic nucleus (about
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Solution: Click For PDF Version Let the width of the infinite square well potential be L. In an
infinite square well the wave function has to vanish at
The wave number k for this wave function will be
and therefore the de Broglie wavelength of a particle in this state will be Using de Broglie equation, we note that the momentum of a particle of mass m in the lowest energy state of an infinite square well of width L will be
and the energy of the lowest energy state will be In the model of the nucleus suggested in the problem, the width of the square well
(a) Mass of an electron
(b) Mass of a neutron
(c) As the binding energy of neutron and proton inside a nucleus is of the order
of MeV, and the energy of neutron as worked out in the infinite square well
model is also of the same order it is reasonable to assume that neutrons and
protons are confined in a size of the order of
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