The magnetic field equations for an electromagnetic wave in free space are , . We have to find (a) the direction of propagation; (b) write the electric field equation; and (c) find whether the wave is polarized, and, if so, find its direction.
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Solution: Click For PDF Version (a)A plane wave characterised by angular frequency and propagation vector can be described by the function . The direction of propagation of the wave is that of the propagation vector . We are given an electromagnetic wave in free space whose magnetic field equations are , and . From these functions, we note that the propagation vector for this wave is , where is the unit vector in the y-direction. Therefore, the direction of propagation of the wave is the negative y-direction. (b) We know that the electric field , the magnetic field , and the Poynting vector , which is in the direction of the propagation vector , are perpendicular to each other and the definition of the Poynting vector is . The magnetic field of the wave is in the direction of the unit vector , and its Poynting vector is in the direction , the electric field vector has to be in the direction . In other words the non-zero component of the electric field of the wave will be . The Maxwell’s equation connecting the electric and magnetic fields that we can use is . Therefore, we have , and
The other components of the electric field of the wave are (c) As the polarization of the wave is determined by its electric field vector , the wave is linearly polarized and its polarization vector is in the direction.
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