We have to show that the half-width of the double-slit interference fringes is given by , if is small enough so that . The half-width is the angle between the two points in the fringe where the intensity is one-half that at the centre of the fringe.
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Solution: Click For PDF Version We first work out the expression for the intensity of the resultant of two coherent waves with phase difference . Let the electric field components of the two waves at a point P at time t be described by the functions
where is the angular frequency of the waves and is the phase difference between them. We note that depends upon the location of the point P, which is described by the angle in a double-slit experiment. We have
where the phase is , and the amplitude is . As the intensity I is proportional to the square of the amplitude, we note that
and for small . And
Let the centre of the m th- fringe be at angle . We have We note that
Let the intensity is one-half that at the centre of the fringe at . We therefore have . This implies that
This implies that
The half-width is the angle between the two points in the fringe where the intensity is one-half that at the centre of the fringe. Therefore, half-width of the fringe will be
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