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579.


Problem 42.20 (RHK)


A radar transmitter T is fixed to a reference frame that is moving to the right with speed u relative to the reference frame S (see figure). A mechanical timer (essentially a clock) in frame , having a period (measured in ) causes transmitter T to emit radar pulses, which travel at the speed of light and are received by R, a receiver fixed in frame S. (a) We have to find the period of the timer relative to observer A, who is fixed in frame S. (b) We have to show that the receiver R would observe the time interval between pulses arriving from T, not as or as , but as

(c) We have to explain why the observer at R measures a different period for the transmitter than measured by observer A, who is in the same reference frame.

Solution:           Click For PDF Version

(a)

As shown in the figure reference frame is moving to the right with speed u relative to the reference frame S. The mechanical timer in is emitting radar pulses at time intervals. The time period of the timer as measured by an observer fixed in S , say A, will be given by the Lorentz dilatation relation

(b)

We next calculate the period of radar pulses measured by the receiver R of S.

We note that as the transmitter of radar waves is moving with speed u with respect to S, it would have moved by distance to the right by the time transmitter in emits successive radar pulse. Therefore, the time period of pulses measured by the receiver R of S will not be but

,

as the radar pulse travel with speed of light c. Therefore, the period of light pulses measured by the radar fixed in S will be

(c)

The difference between and or is that the frequency of pulses emitted by , which is , is Doppler shifted with respect to . The frequency of radar pulses measured by , which is , and frequency of electromagnetic waves as measured by are related by the Doppler relation