Solution:
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It is given that initially the
capacitor is initially charged to 100 V and the
is uncharged. Therefore, an amount of energy

is stored in the
capacitor. The switch
is closed
and the switch
is kept
open for a time interval that will be determined next. The circuit is then a
LC-oscillator with frequency

period

After a lapse of time equal to
the
energy which was initially stored in the
capacitor will be transferred to the 10 H inductor and will be stored in it as
magnetic energy. At this stage the switch
is
opened and the switch
is
closed. We now have a LC-oscillator with frequency

period

The energy in the
when its
potential is 300 V will be

In time
the 4.5
J energy stored in the inductor will be transferred as electrical energy on to
the
capacitor and the potential difference across it then will be 300 V.
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