Solution:
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According to Faraday’s law of induction
,
where
is the
flux enclosed by the closed curve.
(a)
We will calculate
first for the path (a). It is given that the magnetic field is decreasing in
both regions
and
at the
uniform rate of
. We note
that the uniform magnetic field in the region
is
into the plane of the figure. Therefore, induced current will flow in the
clockwise direction to compensate for the decrease in flux in the region
.
But the contour integral is being calculated in the counter-clockwise sense;
therefore, its value will be negative. Therefore,
![](images/pic2536.gif)
(b)
We will calculate
first for the path (b). It is given that the magnetic field is decreasing in
both regions
and
at the
uniform rate of
. We note
that the uniform magnetic field in the region
is coming out of the plane of the figure. Therefore, induced current will
flow in the counter-clockwise direction to compensate for the decrease in flux
in the region
. But the
contour integral is being calculated in the clockwise sense; therefore, its
value will be negative. Therefore,
![](images/pic2537.gif)
(c)
We will calculate
first for the path (c). It is given that the magnetic field is decreasing in
both regions
and
at the
uniform rate of
. As
is
greater than
the net
decrease of flux in the region enclosed by the contour (c) will be
![](images/pic2540.gif)
Therefore, induced current will flow in the counter-clockwise direction to
compensate for the decrease in flux enclosed. The sense of the contour integral
is that of the flow of the induced current; therefore, its value will be
negative. Therefore,
![](images/pic2541.gif)
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