438. Problem 34.31 (RHK) A 22.5-eV positron (positively charged electron) is projected into a uniform magnetic field with its velocity vector making an angle of with . We have to find (a) the period, (b) the pitch p, and (c) the radius r of the helical path. |
Solution: Click For PDF Version It is given that the velocity vector makes an angle of with the magnetic field vector . Magnitude of the magnetic field vector . We will first find the magnitude of velocity of a 22.5-eV positron. We resolve the velocity vector into components, , which is parallel to the field, and ,which is orthogonal to the magnetic field vector . and The radius of the helical path will be determined by and the pitch by . We have The period of the circular orbit is therefore The pitch of the helical path The radius of the helical path |