Problem #0044 Electricity & Magnetism Sub-menu Problem #0046 Chapters Chapters

315.

Problem 29.11 (RHK)

Gauss’ law for gravitationis

where m is the enclosed mass and G is the universal gravitational constant. We will derive Newton’s law of gravitation from this and explain the significance of the minus sign.

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Consider a Gaussian sphere, a sphere of radius r centred at the mass point of mass, m. We assume that the gravitational field due to the mass point is radial and its magnitude is equal for all points at a distance r from it but the direction of the gravitational field varies and is toward the mass point.

We calculate the gravitational flux under the above assumptions. It will be

.

The Gauss’ law for gravitation is

We therefore have

And

which is the Newton’s law of gravitation. The significance of minus sign in the Gauss’ law for gravitation is that the gravitational field due to a mass point is radial and is attractive.