91. Problem 16.19 (RHK) Foucault’s Pendulum A pendulum whose upper end is attached so as to allow pendulum to swing freely in any direction can be used to repeat an experiment first shown publicly by Foucault in 1851. If the pendulum is set oscillating, the plane of oscillation slowly rotates with respect to a line drawn on the floor, even though the tension in the wire supporting the bob and the gravitational pull of the Earth lie in a plane. We have to show (a) that this is a result of the fact
that the Earth is not an inertial frame; (b) that for a Foucault pendulum
at a latitude
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Solution: Click For PDF Version To show the effect of Earth’s West-East rotation Foucault
considered a pendulum at a place at latitude
As Earth is spinning around its polar axis in 24 hours, the angular frequency
of its diurnal rotation
Let R be the radius of the Earth. Speed of rotation about the polar axis of the mid-point of oscillation of the bob is
Time taken by the plane of oscillation of the pendulum to have turned by 3600 will be
At the poles the circular speed of ends B and A will be
At the Equator both ends B and A will have the same angular speed of rotation about the North-South axis as the mid-point O. Therefore, at equator plane of oscillation of the pendulum will remain unchanged. We may note that Foucault pendulum reveals that frame of reference tied up with the Earth is non-inertial and that the effect is more prominent at larger latitudes. |