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84. Problem 18.39 (RHK) Liquid mercury (viscosity, |
)
flows through a horizontal pipe of internal radius 1.88 cm and length
1.26 m. The volume flux is
.We
have to show (a) that the flow is laminar; (b) calculate the
pressure between the two ends of the pipe.|
Solution: Click For PDF Version (a) In order to find whether the flow is laminar we will calculate the Reynolds number
Internal radius of the pipe is 1.88 cm and the volume flux is
Speed of flow of mercury in the pipe
Reynolds number for this speed of flow is
As this is less than 2000, flow is laminar. (b) Volume flux through a pipe of length L and radius r is
Difference in pressure between the two ends of the pipe is
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