47. Problem 13.31P (HRW) Four identical uniform bricks, each of length L, are put on
top of one another in such a way that part of each extends beyond the one
beneath. Find, in terms of L, the minimum value of (a)
|
Solution: Click For PDF Version Key to answering this problem is that for equilibrium and for
requiring the condition of minimum value of displacements
We have been given that the bricks are identical and each brick has length L. The centre of mass of the topmost brick,
We next consider the top two bricks as a block resting on the edge of the third brick, such that the block does not topple. This will happen when the centre of mass of the top two bricks lies on top of the edge of the third brick. We will calculate the centre of mass of the top two bricks,
Making similar calculations as above, we can easily find We thus find |