153. Problem 20.41 (RHK) A tunnel leading straight through a hill greatly amplifies tones at 135 and 138 Hz. We have to find the shortest length the tunnel could have. |
Solution: Click For PDF Version Tunnel can be regarded as a column with open ends. For pressure waves the
ends of the tunnel, as they are open to atmosphere, at resonance will be nodes
of standing waves. This requirement fixes wavelengths,
We next calculate the wavelengths corresponding to frequencies
For
For
We have to find integers
As we are considering two successive overtones we may use that
This implies that
From this result we can obtain the length of the tunnel. It is given by the relation that
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