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135.

Problem 19.43 (RHK)

Vibrations from a 622-Hz tuning fork set up standing waves in a string clamped at both ends. The wave speed for the string is . The standing wave has four loops and is formed by superposition of waves of amplitude 1.90 mm. We have to find (a) the length of the string; (b) equation for the displacement of the string as a function of position and time.

Solution:             Click For PDF Version

Frequency of the tuning fork, .

Wave speed for the string, .

Travelling waves generated in the string by the vibrations of the tuning fork superpose to produce standing waves. Wavelength and frequency f determine the speed v,

As the standing wave in the string has four loops, the length of the string .

Therefore, L = 1.248 m.

Equation of standing waves formed out of travelling wave given by the functions

is given by

It is

We now work out the numerical values of variables in the above function.

The equation of the standing wave is

where x and y are in meter and t is in second.