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123.

Problem 19.19 (RHK)

A wire 10.3 m long and having a mass of 97.8 g/s is stretched under a tension of 248 N. If two pulses, separated in time by 29.6 ms, are generated one at each end of the wire, we have to find where the pulses will meet.

Solution:             Click For PDF Version

Data of the problem are:

length of the wire, l = 10.3 m;

mass of the wire, m = 97.8 g.

Mass per unit length of the wire will be,

Wire is under tension, T = 248 N.

Speed of transverse wave motion in the wire will therefore be

Distance travelled by the first pulse in 29.6 ms from the end where it is generated will be

Distance of the position from the other end of the wire will be

As the second pulse is released from the second end of the wire at 29.6 ms, the two pulses will meet at a distance y from the first end, given by