120. Problem 15.55 (RHK) A simple pendulum of length L and mass m is suspended in a car that is travelling with a constant speed v around a circle of radius R. Pendulum undergoes small oscillations in a radial direction about its equilibrium position. We have to find the frequency of oscillation. |
Solution: Click For PDF Version It is given that a bob with a string is hanging in a car that is travelling with a constant speed v around a circle of radius R. The required centripetal force is obtained by the incline of the string attached to the bob by angle from the vertical. The component of the weight of the bob perpendicular to the string provides the centripetal force, that is
Let the bob be displaced by a small angle . We will show that for small oscillation the bob will execute simple harmonic motion as a simple pendulum. When the pendulum is displaced by an additional angle restoring force on the bob will be
Let us consider motion in a uniformly rotating frame with angular speed . Let the length of the string with which the bob is hanging be L. Equation of motion of the bob in this frame of reference will be
Under the approximation , equation of motion reduces to the form
Using the result
equation of motion simplifies to the form
It is an equation of SHM. Frequency of oscillation is
where T is the period of oscillation. Frequency of the pendulum is
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