(a) We have to calculate the rate of heat loss through a glass window of area and thickness 3.0 mm if the outside temperature is and the inside temperature is . (b) A storm window is installed having the same thickness of glass but with an air gap of 7.5 cm between the two windows. We have to calculate the corresponding rate of heat loss presuming that conduction is the only important heat-loss mechanism.
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Solution: Click For PDF Version (a) Inside temperature is Outside temperature is
Thermal conductivity of glass is Area of the glass window is Thickness of glass is Therefore, the rate of heat loss through the glass window can be calculated from the heat conduction equation
Substituting the numerical values from the data above, we get
(b) We will compute the rate of heat loss from inside of the room to the outside when a storm window of thickness 3 mm but with an air gap of 7.5 cm between the two windows has been installed. Thermal conductivity of air is We will use the result that the rate of heat transfer through a compound slab consisting of materials having thicknesses , , and thermal conductivities , , is given by the generalisation of the heat conduction given equation
Substituting the data, we find
We notice that the heat flow is determined essentially by the air gap, as air has very low heat conductivity in comparison to that of glass.
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