We have to verify that the binding energy per nucleon for is . The needed atomic masses are 239.052158 u (), 1.007825 u (), and 1.008665 u (neutron).

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The atomic number of nucleus is 94. We note therefore a nucleus is a bound system of 94 protons and 145 neutrons. The total binding energy of 239 nucleons in a nucleus, which is equal to the mass defect times , will, therefore, be

As

,

we have

Therefore, the binding energy per nucleon in nucleus will be