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684.


Problem 47.33 (RHK)


An x-ray beam, containing radiation of two distinct wavelengths, is scattered from a crystal, yielding the intensity spectrum, as shown in the figure. The interplanar spacing of the scattering planes is 0.94 nm. We have to determine the wavelength of the x rays present in the beam.

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The Bragg’ law for crystal diffraction is

where d is the lattice spacing.

From the figure we note that the scattering angles are small and .

From the intensity pattern shown in the figure, we note that diffraction intensity peaks at correspond to first and second diffraction orders for one wavelength, and those at correspond to the first and second diffraction orders for the second wavelength.

We thus have

The lattice spacing

Using the Bragg’s law we find that the radiation contains the following two wavelengths;