Optics SUB-MENU Optics Sub-menu Problem NoChaptersChapters


632.


Problem 45.13 (RHK)


In the front of a lecture hall, a coherent beam of monochromatic light from a helium-neon laser illuminates a double slit. From there it travels a distance of 20.0 m to a mirror at the back of the hall, and returns the same direction to a screen. (a) We have to fix the distance between the two slits in order that the distance between the interference maxima is observed to be 10.0 cm. (b) We have to state the change in interference pattern if the lecturer inserts in front of one of the slits a cellophane that contains 2.5 more waves than a path through air of the same geometric thickness.


Solution:           Click For PDF Version

(a)

A mirror has been kept at a distance of 20.0 m from the double slit. Thus image of the slits is formed at a distance of 20.0 m behind the mirror. As the interference pattern is observed on a screen facing the mirror, the effective distance of the screen from the virtual images is 40.0 m.

The distance between the interference maxima will be given by the double-slit condition

,

where d is the distance between the slits, and D is the distance from the slits to the screen. As we have stated above, in the experimental set up described in the problem . We want for laser light of wavelength . We thus find that

(b)

When cellophane that contains 2.5 more waves than a path through air of the same geometric thickness is inserted in front of one of the slits, the phase difference between the rays changes by . As a result in the interference pattern maxima and minima get interchanged.