A light bulb is suspended 250 cm above the surface of the water in a swimming pool; as shown in the figure. The water is 186 cm deep and the bottom of the pool is a large mirror. We have to find the distance of the image of the light bulb when viewed from near normal incidence.
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Solution: Click For PDF Version From the Snell’s laws of refraction we know that the depth, d, of a pool of water, refractive index n, when viewed from above at normal incidence to the surface of the water will appear to be
We have taken
for the refractive index of water,
It is given
that the distance of the light bulb from the surface of the water is
250 cm. Therefore, the image of the light bulb as reflected from the
bottom surface of the pool when viewed from near normal incidence
will be about
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from the mirrored surface at the bottom of the pool.