Problem #0225 Electricity & Magnetism Sub-menu Problem #0227 Chapters Chapters

496.

Problem 36.29 (RHK)

The armature of a motor has 97 turns each of area and rotates in a uniform magnetic field of A potential difference of 24 V is applied. If no load is attached and friction is neglected, we have to find the rotational speed at equilibrium.

Solution:             Click For PDF Version

We will first find the expression for the induced emf assuming that a coil of area A and made of n turns is rotated uniformly in a magnetic field B with frequency .

Flux across the armature will be

,

And induced emf will be

At equilibrium the induced emf has to be equal and opposite to the applied emf, so that there is no flow of current and there is no net force on the coil due to magnetic field.

We now use the data for finding thee frequency .

Therefore,

The rotational speed at equilibrium will be 6.28 revolutions per second.